Thursday, March 28, 2013

A Geometric Puzzle







Find the area enclosed by the 4 arcs in the figure (shaded in grey)

The figure is drawn as below

1. A square is drawn with side "a'

2. With the side of square as radius, 4 quadrants are drawn with centre at each of the vertices.


2 comments:

  1. Based on the symmetry of the figure, there are 6 kinds of areas of interest in here.
    1) Area of square (S)
    2) Area of quadrant (Q)
    3) Area of eye shape (E)
    4) Area of 'M' (or wing) shape (formed between the square & the intersection of the two eye shapes) (M)
    5) Are of 'A' shape (A)
    5) Area that you asked for. (?)

    E = Q - (S-Q) = 2Q-S
    M+H = (S*(S/2))/2 =====> (a)
    M+(M+H) = S-Q
    M = S-Q -(a) =====> (b)

    M = (S-2E+?)/4

    ? = 4M+2E-S

    ? = 4(b) + 2E -S

    -Ashok.



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  2. 4M+2E-S is correct.

    Area of E can easily be calculated.

    But I have not understood how you have calculated the area of M.

    By the way, what is H above?

    I do not get this equation. M+H = (S*(S/2))/2 =====> (a)

    Why are you multiplying area of the square with itself. Or, is that you are calculating area of some triangle? What is S above in equation (a)


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